Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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Answer: (2;-9).
Step-by-step explanation:
Answer:
See solutions below
Step-by-step explanation:
From the given diagram;
AC = opposite
AB = 7 = hypotenuse
Angle of elevation = 70 degrees
Using SOH CAH TOA
Sin theta = opp/hyp
Sin theta = AC/AB
Sin 70 = AC/7
AC = 7sin70
AC = 7(0.9397)
AC = 6.58
Similarly
tan 70 = AC/BC
tan 70 = 6.58/BC
BC = 6.58/tan70
BC = 6.58/2.7475
BC = 2.39
tan m<A = BC/AC
tanm<A = 2.39/6.58
tan m<A = 0.3632
m<A = 19.96degrees
Answer:
A=(1,6) B=(1,6)
Step-by-step explanation:
Its the absolotle value between them.
