11 5/9 + 10 1/3 plz help

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

10 1/3= 31/3
31/3= 93/9

11 5/9= 104/9
93/9 + 104/9 = 197/9
197/9= 21 8/9

your answer is 21 & 8/9

Good Luck
XD

You might be interested in

An employee at a department store is stocking cell phone cases. He has a box of 80 cases. Among the 80 cases, 40 are black, 10 a

Salsk061 [2.6K]

Answer:

$\sf \dfrac{203}{4108}$

As a decimal = 0.05 (nearest hundredth)

Step-by-step explanation:

$\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}$

First pick:

$\sf \implies P(pink)=\dfrac{30}{80}$

As the case is NOT replaced, second pick:

$\sf \implies P(pink)=\dfrac{30-1}{80-1}=\dfrac{29}{79}$

As the case is NOT replaced, third pick:

$\sf \implies P(pink)=\dfrac{29-1}{79-1}=\dfrac{28}{78}$

Therefore,

$\sf \implies P(pink \ and \ pink \ and \ pink)=\dfrac{30}{80} \times \dfrac{29}{79} \times \dfrac{28}{78}=\dfrac{203}{4108}$

Answer as a decimal = 0.05 (nearest hundredth)

6 0

3 years ago

find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)

Paraphin [41]

This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c

c = 1

If c =1,

6 = a + 1
a = 5

This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?

5 0

4 years ago

I need help with #11 - #14.

Aleonysh [2.5K]

Answer:

I can get you jump started a bit.

Step-by-step explanation:

So Each of those pairs of figures are Similar.

This means they have equal angle measures but different side lengths.

To find it, we have to make a Proportion:

Example: #11

$\frac{x+1}{3x+1} =\frac{8}{20}$