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horrorfan [7]
3 years ago
7

An arrow is fired at 5.20 m s−1 at an angle of 22.0° above the horizontal. Find the horizontal component of the initial velocity

, expressing your answer in m s−1 to 2d.P.\
Physics
1 answer:
Inessa [10]3 years ago
7 0

Answer:

4.82ms^{-1}

Explanation:

We are given that

Initial velocity, u=5.20m/s

\theta=22^{\circ}

We have to find the horizontal component of the initial velocity.

We know that

Horizontal component of velocity=ucos\theta

Using the formula

Horizontal component of the initial velocity=5.2cos22^{\circ}

Horizontal component of the initial velocity=5.2\times 0.9272

Horizontal component of the initial velocity=4.82ms^{-1}

Hence, the horizontal component of the initial velocity=4.82ms^{-1}

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Verdich [7]

Answer:

2.5m/s2

Explanation:

The following were obtained from the question:

F = 600N

M = 240 kg

a =?

Recall: F = Ma

a = F/M

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Answer:

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In a two planet system, does an increase in planet velocity result in a decreased period?
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Answer:

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