Question

An arrow is fired at 5.20 m s−1 at an angle of 22.0° above the horizontal. Find the horizontal component of the initial velocity, expressing your answer in m s−1 to 2d.P.\

Answer 1

Answer:

$4.82ms^{-1}$

Explanation:

We are given that

Initial velocity, u=5.20m/s

$\theta=22^{\circ}$

We have to find the horizontal component of the initial velocity.

We know that

Horizontal component of velocity=$ucos\theta$

Using the formula

Horizontal component of the initial velocity=$5.2cos22^{\circ}$

Horizontal component of the initial velocity=$5.2\times 0.9272$

Horizontal component of the initial velocity=$4.82ms^{-1}$

Hence, the horizontal component of the initial velocity=$4.82ms^{-1}$