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3 years ago

If y=10 and x=2 what is the constant of variation (k)?

Mathematics

2 answers:

ki77a [65]3 years ago

8 0

K is always equal to y/x. So 10/2=5.

yarga [219]3 years ago

7 0

Answer:

Step-by-step explanation:

hope this helps

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Find the value of x in the triangle.

Studentka2010 [4]

Answer:

164

Step-by-step explanation:

Remember, everytriangle is 180 all together. So add what you see and subtract it from 180.

9+7= 16

180-16= 164

Hope it helps

5 0

2 years ago

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant = 0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

$N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g$

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0

3 years ago

A two-factor study with two levels of factor A and three levels of factor B uses a separate group of n = 5 participants in each

Mashcka [7]

Answer: There are 30 participants are needed for the entire study.

Step-by-step explanation:

Since we have given that

Number of levels of factor A = 2

Number of levels of factor B = 3

Number of participants in each treatment condition = 5

So, the number of participants are needed for the entire study is given by

$2\times 3\times 5\\\\=6\times 5\\\\=30$

Hence, there are 30 participants are needed for the entire study.

7 0

3 years ago

Evaluate the expression below. 18 - 71.4 + 3(-1) 0 1 0-7 0-1 07

Vsevolod [243]

Answer:

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2 years ago

At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a

laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0

3 years ago

If y=10 and x=2 what is the constant of variation (k)?​

If y=10 and x=2 what is the constant of variation (k)?