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Leni [432]
3 years ago
10

A hula hoop has a three foot diameter how far will it travel in 6 revolution

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
<h2>Answer:</h2>

<u>It will travel  </u><u>56.52 ft</u><u> in 6 revolution.</u>

<h2> Explanation:</h2>

We know that Circumference  of circle = 2πr

where diameter is already given so by putting it in the formula we get the following result for radius(r)

Diameter = 3 ft

Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

So circumference of loop is:

Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

We have to  find the distance traveled in 6 revolution

As we know that distance traveled in one revolution =  9.42 ft

So distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft

Nesterboy [21]3 years ago
4 0

Answer:

Distance traveled in 6 revolution = 56.52 ft

Step-by-step explanation:

Formula:

Circumference  of circle = 2πr

r - Radius of circle

It is given that,

A hula hoop has a three foot diameter.

Diameter = 3 ft

Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

<u>To find the circumference of loop</u>

r = 1.5 ft

Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

<u>To find the distance traveled in 6 revolution</u>

Distance traveled in one revolution =  9.42 ft

Distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft

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