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djyliett [7]
3 years ago
15

Solve for y. 6 over 36 equals y over 3

Mathematics
1 answer:
Travka [436]3 years ago
6 0

Answer:

Y = 1/2

Step-by-step explanation:

6/36 = y/3

Y = 1/2

Just multiply 3 by both sides

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Find the distance between R(-5,-3) and S(4,-2).​
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Step-by-step explanation:

<em>to </em><em>calculate</em><em> </em><em>the </em><em>distance</em><em> between</em><em> </em><em>two </em><em>points</em><em> </em><em>on </em><em>an </em><em>xoy </em><em>plane </em><em>you </em><em>use </em><em>the </em><em>formula</em>

<em>√</em><em>(</em><em>x2-x1</em><em>)</em><em>²</em><em>+</em><em>(</em><em>y2-y1</em><em>)</em><em>²</em>

<em>in </em><em>this </em><em>case </em><em>x1 </em><em>is </em><em>-</em><em>5</em><em>,</em><em>x2 </em><em>is </em><em>4</em><em>,</em><em>y1 </em><em>is </em><em>-</em><em>3</em><em> </em><em>and </em><em>y2 </em><em>is </em><em>-</em><em>2</em><em> </em><em>therefore</em><em> </em><em>the </em><em>solution</em><em> will</em><em> be</em>

<em>√</em><em>(</em><em>4</em><em>-</em><em>(</em><em>-</em><em>5</em><em>)</em><em>²</em><em>+</em><em>(</em><em>-</em><em>2</em><em>-</em><em>3</em><em>)</em><em>²</em>

<em>√</em><em>(</em><em>4</em><em>+</em><em>5</em><em>)</em><em>²</em><em>+</em><em>(</em><em>-</em><em>5</em><em>)</em><em>²</em>

<em>√</em><em>(</em><em>9</em><em>)</em><em>²</em><em>+</em><em>(</em><em>-</em><em>5</em><em>)</em><em>²</em>

<em>√</em><em>8</em><em>1</em><em>+</em><em>2</em><em>5</em>

<em>√</em><em>1</em><em>0</em><em>6</em>

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3 0
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Can anyone help me with these?<br> It would be a big help:)
stira [4]

1) \frac{1}{x+7}
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7 0
4 years ago
The 4 cities(A,B,C&amp;D) are to be connected by roads.The budget allows 22 km of road to be build. How can it be done? In the g
Pie

Answer:

The roads are 4 km , 4 km, 4 km , 4 km and 6 km.

Step-by-step explanation:

From the first diagram below, for the 4 cities to be connected all the roads will be 32 km but the budget only allows for 22 km roads.  The second diagram demonstrate how you could build a 22 km road that connects the 4 cities.

The square ABCD all the sides are equal. Base on the diagram 2 triangles are formed.

The length of the hypotenuse can be found using Pythagoras formula.

c² = a² + 4²

c² = 16a²

square both sides

c = √16a²

c = 4a

The hypotenuse of the right angle triangles formed are 4a.

The length of the line joining the 2 triangles  can be solved as 8 - a - a = 8 - 2a.

Now recall the roads all together is 22 km.

Therefore,

add the hypotenuse of the 4 right angle triangle and  8 - 2a to connect the 4 cities.

4a + 4a + 4a + 4a + 8 -2a = 22

16a -2a + 8 = 22

14a + 8 = 22

14a = 22 - 8

14a = 14

a =14/14

a = 1

replace the value of a in all the sides

the road will be

4(1) + 4(1) + 4(1) + 4(1) + 8 - 2(1) = 22 km

The roads are 4 km , 4 km, 4 km , 4 km and 6 km.

3 0
3 years ago
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