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3 years ago

For which sample size (n) and sample proportion (p) can a normal curve be

Mathematics

2 answers:

melomori [17]3 years ago

8 0

The answer i reallyyyyyyyyyyy d

larisa86 [58]3 years ago

4 0

Answer: Thank you so much !! I had the exact one!!

D. n=35 p =0.7

Step-by-step explanation:

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Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is start fraction 1 over 6 e

Alona [7]

Answer: B. one-third

Step-by-step explanation:

Probability of picking a red marble, P(R) = 1/6

Probability of picking a yellow marble, P(Y) = 1/2

Therefore, the probability of picking a blue marble will be:

= 1 - (P(R) + P(Y))

= 1 - (1/6 + 1/2)

= 1 - (4/6).

= 1 - 2/3

= 1/3

The probability of picking a blue marble will be one third

8 0

3 years ago

PLS HELP. What does it mean when there is a small number to the bottom right of a base number? It's kinda like a exponent but on

KATRIN_1 [288]

THe number on the bottom is called the Notation

6 0

3 years ago

Alex is making a pizza. The round pizza pan has a 16 inch diameter. What is the area of the pizza crust needed to fill the entir

Lubov Fominskaja [6]

Answer:

The area of the pizza crust is 200.96 inches²

Step-by-step explanation:

* Lets explain how to solve the problem

- The area of any circle is πr² , where r is the length of its radius

- The length of the diameter of any circle is twice the length of

its radius (diameter = 2 radius)

* Lets solve the problem

- Alex is making a pizza

- The round pizza pan has a 16 inch diameter

- To find the area of the pizza crust is needed to fill the entire pan,

calculate the area of the pan

∵ The diameter of the pan is 16 inches

∵ The radius of the pan = 1/2 diameter

∴ The radius of the pan = 1/2 (16) = 8 inches

∵ The area of the pan = πr²

∵ π = 3.14 and r = 8 inches

∴ The area pf the pan = 3.14 (8)² = 200.96 inches²

∵ The area of the pizza pan = the area of the pizza crust

∴ The area of the pizza crust is 200.96 inches²

7 0

3 years ago

Solve the equation 6w2 – 7w – 20 = 0.

azamat

For this case we have the following quadratic equation:

$6w ^ 2-7w-20 = 0$

Where:

$a = 6\\b = -7\\c = -20$

Its roots will be given by:

$w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}$

The roots are:

$w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}$