Work out m and c for the line:<br> y = X

inn [45]

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

In order to find the answer, we need to do as follows:

Average no. of people per km^2 = total no. of people ÷ total no. of people

Average no. of people per km^2 = 1, 080, 264, 388 ÷ 2, 973, 190

Average no. of people per km^2 = 363.335134317

Now we need to round the answer to the nearest whole number. In this case, we will be rounding down as displayed below:

Average no. of people per km^2 = 363 people

ANSWER:

Therefore, the answer is:

There are an average of 363 people per km^2 of land in India.

Please mark as brainliest if you found this helpful! :)
Thank you <3

7 0

2 years ago

Robin was just hired at Groceries & More as a cashler. They pay her $12 an hour. She works 20 hours a week and is going to s

Lostsunrise [7]

Answer:

5 weeks

Step-by-step explanation:

We know that she works at a rate of $12 an hour, she also works 20 hours a week.

The total amount she makes per week is $240 (12 x 20). However, that is without deductions. We have to subtract $34 from the $240.

$240 - $34 = $206.

$206 is the amount she makes in a week and she wants to save $950. How many weeks does she have to save? Well, let's divide.

$950 / $206 = 4.6 weeks. However, if we have to round up to 5 weeks.

4 0

1 year ago

The Empire State Building is just over 1,450 feet tall. In anticipation of visiting this landmark on your vacation, you create a

Sergio [31]

Answer:

365 and 1/2 blocks will be used

The scale fact is 0.25

Step-by-step explanation:

So . .

We create a ratio 1:2

This represents 1 block is equivalent to 2 feet

Simply 1450 ÷ 2 = 725

So . . There are 725 feet and because One block is equal to 2 feet you divide 725 ÷ 2 = 362.5 blocks will be used

To find the scale factor simply divide the deminsions of the new shape by old

362.5 ÷ 1450 = .25

5 0

1 year ago

You want a snack. One small pear has 100 calories. A small plum has 45 calories. What is the ratio of the calories in a plum to

Anvisha [2.4K]

The ratio would be
45/100
45 to 100
45:100

Hope this helps!

7 0

3 years ago

Read 2 more answers

Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer

agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming: the function is $f(x)=x^{2}$ in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

$g'(0)=g'(1)$

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

$g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0$

$g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2$

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

$f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]$

This is what the Bilateral Theorem says:

$\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L$

4 0

3 years ago

Work out m and c for the line: y = X – 2