Complete the table for the function y = 0.1^x
The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.
* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).
* 0.1^-1 = 1/0.1 = 10
* 0.1^0 = 1 : (Remember this rule: a^0 = 1)
* 0.1^1 = 0.1
Our list of values: 100, 10, 1, 0.1
Now, we can plug these values into your table:
![\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26y%5C%5C2%2610%5C%5C1%2610%5C%5C0%261%5C%5C1%260.1%5Cend%7Barray%7D%5Cright%5D)
The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]
I hope this helped!
Answer:
3
Step-by-step explanation:
because that's the communicative property
Hello,
The formula for finding the area of a circular region is:
then:
With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.
Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
Answer:
(0, 3 )
Step-by-step explanation:
Given the 2 equations
x + 3y = 9 → (1)
- 2x + 2y = 6 → (2)
Multiplying (1) by 2 and adding to (2) will eliminate the x- term
2x + 6y = 18 → (3)
Add (2) and (3) term by term to eliminate x, that is
0 + 8y = 24
8y = 24 ( divide both sides by 8 )
y = 3
Substitute y = 3 into either of the 2 equations and solve for x
Substituting into (1)
x + 3(3) = 9
x + 9 = 9 ( subtract 9 from both sides )
x = 0
solution is (0, 3 )
