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Rudik [331]
3 years ago
10

The length of a rectangular deck is 4 times it’s width. If the deck’s perimeter is 30ft, what is the deck’s area?

Mathematics
1 answer:
ioda3 years ago
7 0

Try this solution (note, this is not the shortest way):

1. if the given length is 'l' and the width is 'w', then according to the condition 4*l=w;

2. according to the condition the perimeter is 30 ft. Formula of the perimeter is P=2(l+w), then 2(l+w)=30;

3. if to substitute '4*l' instead of 'w', the formula of the perimeter (from item no. 2) will be as 2(4*l+l)=30 or 10*l=30 ⇒ l=3 ft. The length is 3 ft.!

4. if l=3 ft., then w=4*3=12 ft. The width is 12 ft.!

5. Area is

A=w*l; A=12*3=<u>36 ft²</u>

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Answer:

Piper's claim is not correct.

Step-by-step explanation:

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3 years ago
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Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

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At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
How many 2-digit numbers are multiples of either 5 or 7?
Svet_ta [14]

Answer:

46

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he count of numbers from 1 to n that are divisible by k is integer part of (n/k).

So the numbers from 1 to 99 divisible by 3 is int(99/3) = 33

Those divisible by 5: int(99/5) = 19

From the sum of those two, subtract those divisible by 15 = int(99/15) = 6

That gives you 33+19-6 = 46.

Now subtract the 1 digit numbers: 3, 5, 6, 9, or four of them

46 - 4 = 42 is the answer.

4 0
3 years ago
Read 2 more answers
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