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Rudik [331]
3 years ago
10

The length of a rectangular deck is 4 times it’s width. If the deck’s perimeter is 30ft, what is the deck’s area?

Mathematics
1 answer:
ioda3 years ago
7 0

Try this solution (note, this is not the shortest way):

1. if the given length is 'l' and the width is 'w', then according to the condition 4*l=w;

2. according to the condition the perimeter is 30 ft. Formula of the perimeter is P=2(l+w), then 2(l+w)=30;

3. if to substitute '4*l' instead of 'w', the formula of the perimeter (from item no. 2) will be as 2(4*l+l)=30 or 10*l=30 ⇒ l=3 ft. The length is 3 ft.!

4. if l=3 ft., then w=4*3=12 ft. The width is 12 ft.!

5. Area is

A=w*l; A=12*3=<u>36 ft²</u>

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Total number of different possible outcomes =

       total number of different possible values of the last 2 digits

   =  the quantity of numbers from  00  to  99

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6 0
3 years ago
A parallelogram has an area of x2 + 9x - 36.
malfutka [58]

Answer:

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:

A = x^2 + 9x - 36.  This factors into A = (x + 12)(x - 3).  We can assume that the length of the parallelogram is x + 12 and that the width is x - 3.

Note that if x = 3 the area becomes zero.  So:  x must be greater than 3, so that the (x - 3) factor is positive.

Example:  If x = 4, then the dimensions of the parallelogram are 4 + 12, or 16, and 4 - 3, or 1.  

5 0
3 years ago
If m and n are off then is mn even?
11111nata11111 [884]

Answer:

No, mn is not even if m and n are odd.

If m and n are odd, then mn is odd as well.

==================================================

Proof:

If m is odd, then it is in the form m = 2p+1, where p is some integer.

So if p = 0, then m = 1. If p = 1, then m = 3, and so on.

Similarly, if n is odd then n = 2q+1 for some integer q.

Multiply out m and n using the distribution rule

m*n = (2p+1)*(2q+1)

m*n = 2p(2q+1) + 1(2q+1)

m*n = 4pq+2p+2q+1

m*n = 2( 2pq+p+q) + 1

m*n = 2r + 1

note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.

The result 2r+1 is some other odd number as it fits the form 2*(integer)+1

Therefore, multiplying any two odd numbers will result in some other odd number.

------------------------

Examples:

  • 3*5 = 15
  • 7*9 = 63
  • 11*15 = 165
  • 9*3 = 27

So there is no way to have m*n be even if both m and n are odd.

The general rules are as follows

  • odd * odd = odd
  • even * odd = even
  • even * even = even

The proof of the other two cases would follow a similar line of reasoning as shown above.

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5 0
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