Question

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Answer 1

Answer:

$\frac{3 {x}^{2} }{2y {}^{4} }$

Step-by-step explanation:

$\frac{21x {}^{6}y {}^{5} }{14 {x}^{2} y {}^{9} }$

i) divide the numbers

$( \frac{21}{14})( \frac{x {}^{6} y {}^{5} }{ {x}^{2}y {}^{9} })$

$( \frac{3}{2} )( \frac{x {}^{6} y {}^{5} }{ {x}^{2}y {}^{9} })$

ii) simplify the like terms with the same base by substracting their exponents

$( \frac{3}{2} )(x {}^{6 - 2} y {}^{5 - 9} )$

$( \frac{3}{2} )(x {}^{4} y {}^{ - 4} )$

$\frac{3x {}^{2} }{2y {}^{4} }$