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IRINA_888 [86]
3 years ago
7

Help Me With This Question

Mathematics
1 answer:
kumpel [21]3 years ago
6 0
A) 2/4

b) i: 2/5*1/4= 2/20=1/10
    ii:(3/5*2/4)+(2/5*3/4)=(6/20)+(6/20)=3/10+3/10=6/10

c) It seems like there is a lack of information on the tree diagram so I could not answer this.

Hope this helps :)
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26 over 28- 13 over 28
kkurt [141]

Answer:

13/28 (13 over 28)

Step-by-step explanation:

26/28 - 13/28 = 13/28 and since 13 is a prime number it can't be simplified

7 0
3 years ago
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Divide 1/2 and 3/4 and it can not be a mixed number.
mamaluj [8]

Answer:

Many options - 4/6 or 2/3 or 0.66

Step-by-step explanation:

When dividing fractions, we use KCF (keep, change, flip) so our new equation is 1/2 x 4/3. Just multiply! Your answer should be 4/6, and if it needs to be simplified, the answer is 2/3. The answer as a decimal is 0.66 !

4 0
2 years ago
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What is the sum? StartFraction 3 y Over y squared + 7 y + 10 EndFraction + StartFraction 2 Over y + 2 EndFraction
katovenus [111]

Answer:

\dfrac{5}{y+5}

Step-by-step explanation:

Here, we have to find the sum of 2 fractions:

1st fraction: \dfrac{3y}{y^{2}+7y+10}

2nd fraction: \dfrac{2}{y+2}

Considering the denominator of 1st fraction:

y^{2}+7y+10

Using factorization method:

7y can be written as (2y + 5y).

\Rightarrow y^{2}+2y+5y+10

Taking <em>5 common</em> from 5y+10 and <em>y common</em> from y^{2}+2y: \Rightarrow y(y+2)+5(y+2)

Now taking (y+2) common:

\Rightarrow (y+5)(y+2)

\dfrac{3y}{y^{2}+7y+10} can be written as \dfrac{3y}{(y+5)(y+2)}

Now, calculating the sum:

\dfrac{2y}{(y+5)(y+2)} + \dfrac{2}{y+2}

Taking <em>LCM</em> and solving:

\Rightarrow \dfrac{3y+2(y+5)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5y+10}{(y+5)(y+2)}\\\Rightarrow \dfrac{5(y+2)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5}{(y+5)}

Hence, answer is \dfrac{5}{y+5}.

4 0
3 years ago
Skye says that x^3 – a^3 = (x – a)(x^2 + ax + a^2) is a polynomial identity because when she substitutes 2 in for x and 3 in for
Nady [450]

Answer:  x^3 - a^3 = (x - a) (x^2 + ax + a^2) is an identity

Step-by-step explanation:

Verify the identity using trig rules.

5 0
2 years ago
What's the explicit rule for the sequence 3, -6, 12, -24, 48, ...?
777dan777 [17]

Answer:

\sf \dfrac{-3}{2}(-2)^n

Step-by-step explanation:

Explicit formulas are used to represent all the terms of the geometric sequence with a single formula.

  \sf \boxed{\bf t_n = ar^{n-1}}

a is the first term.

r is the common ratio.

r = second term ÷ first term.

   3 , - 6 , 12, - 24, 48 ,........

a = 3

r = -6 ÷ 3 = -2

         \sf t_n = 3*(-2)^{(n-1)}\\\\

             \sf = 3*(-2)^{n}*(-2)^{-1}\\\\ =3*(-2)^n*\dfrac{-1}{2}\\\\= \dfrac{-3}{2}(-2)^n

Check:

\sf t_1 =\dfrac{-3}{2}*(-2)^1=\dfrac{-3}{2}*(-2) = 3\\\\\\t-2 = \dfrac{-3}{2}*(-2)^2 = \dfrac{-3}{2}*4=-6\\\\\\t_3=\dfrac{-3}{2}*(-2)^3=\dfrac{-3}{2}*(-8)=12

4 0
1 year ago
Read 2 more answers
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