Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
Answer:
|3x + 4 | + 6
Step-by-step explanation:
(f+g)(x)= f(x) + g(x)
= |3x+4| + 2 + 4
= | 3x + 4 | + 6
Area for square = s² = 196x¹²y¹⁰z⁶
s = √(<span>196x¹²y¹⁰z⁶)
s = 14x</span>⁶y⁵z³
Perimeter = 4*s = 4*(14x⁶y⁵z³) = 56x<span>⁶y⁵z³
Perimeter = 56</span>x<span>⁶y⁵z³ D</span>
Answer: 2.36
Step-by-step explanation:
Using the μ=∑[x⋅P(X=x)
U will need to do
2/11 because you have 2 labeled 1
3/11 because you have 3 labeled 2
6/11 because you have 6 labeled 3
Then you will do:
1 x 2/11 = 0.18
2 x 3/11 = 0.5454 = 0.55
3 x 6/11 = 1.63
Then add them all together to find the μ
0.18 + 0.55 + 1.63 = 2.36
Hope that helps, plz put a good rating
