W=80
365 subtract by all the other angles
9514 1404 393
Answer:
x = 12
Step-by-step explanation:
The square of the length of the tangent segment is equal to the product of lengths from the external common point to the two circle intersections of the secant.
x^2 = (2)(70+2)
x^2 = 144
x = √144
x = 12
A)
Triangle ABX
Height = 8m
Base = 26-11 m
Find length by AB^2 = 15^2 + 8^2
b) Find AC by using AB as Height and BC as base
AC^2 = AB ^2 + BC ^2
2/3 x 3/9 =
6/9 x 3/9
18/81=
6/27
therefore, the answer is 6/27