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3 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?

Mathematics

1 answer:

sergeinik [125]3 years ago

8 0

Solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

$(\sqrt[3]{8})^x$

Solving:

We know 8= 2x2x2= 2^3

and $\sqrt[3]{x}=x^{\frac{1}{3}}$

Applying these rules:

$=((2^3)^{\frac{1}{3}})^x$

$=(2^{\frac{3}{3}})^x\\$

$=2^x$

So, solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Keywords: Radical Expression

Learn more about Radical Expression at:

#learnwithBrainly

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3 years ago

Mary bought 1 1/2kg of apples and Nancy bought 3 5/6 kg. How many kg did they buy all together.

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4 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let X denote the heights of women in the USA.

It is provided that X follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

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3 years ago

Three of these expressions are equal to the volume of the barn shown. Which expression is not?

timurjin [86]

The statement that does not match the others is the one at lower right.

_____

The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the upper right expression is a true represenation of the barn's volume:

... Volume of triangular prism + Volume of rectangular prism

The volume of a rectangular prism is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...

... Volume of rectangular prism = a·b·c

The volume of a triangular prism is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...

... Area of triangular barn end = (1/2)b(d-c)

Since the length of the barn is "a", the volume of the triangular prism is ...

... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)

The total volume is the sum of the volumes of the parts ...

... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the upper right selection

This can be factored by removing a·b to outside parentheses:

... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the lower left selection

___

Since the two left selections match the one at upper right, the odd one is the one at lower left.