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RideAnS [48]
3 years ago
15

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

Solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

(\sqrt[3]{8})^x

Solving:

We know 8= 2x2x2= 2^3

and \sqrt[3]{x}=x^{\frac{1}{3}}

Applying these rules:

=((2^3)^{\frac{1}{3}})^x

=(2^{\frac{3}{3}})^x\\

=2^x

So, solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Keywords: Radical Expression

Learn more about Radical Expression at:

  • brainly.com/question/7153188
  • brainly.com/question/10534381

#learnwithBrainly

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3 years ago
Solve for x: −2x − 4 > 8
Pavlova-9 [17]
To solve for x in an inequality is very similar to solving for x in an equation since for both you would need to isolate x. 

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             -2x> 12

step 2) x< -6                 Divide out the -2 to isolate x, however, keep in mind,                                      when you divide or multiply over any negative                                                   number, you must also remember to flip the inquality                                      sign.


Answer: x<-6
6 0
3 years ago
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8/v + 9/x=y Solve for v​
Andreas93 [3]

The answer is v= -8x/-xy+9

Here is the step by step process (This is going to be long):

1.  9v+8x=vxy

Multiply both sides by vx

2.  9v+8x+−vxy=vxy+−vxy

−vxy+9v+8x=0

Add -vxy to both sides

3.  −vxy+9v+8x+−8x=0+−8x

−vxy+9v=−8x

Add -8x to both sides

4.  v(−xy+9)=−8x

Factor out the variable v

5.  v(-xy+9)/-xy+9 = -8x/-xy+9

v = -8x/-xy+9

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3 years ago
In country X, the average yearly salary of 50-year-olds with 16 years of education is $50,275, while the average yearly salary o
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Answer:

38%

Step-by-step explanation:

The additional wage compared 12 years of education to 16 years of education is:

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3 0
3 years ago
Simplify 4x^2 / 3 X 6/ 8x
Leokris [45]

Answer:

x

Step-by-step explanation:

The answer to

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