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2 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?

Mathematics

1 answer:

sergeinik [125]2 years ago

8 0

Solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

$(\sqrt[3]{8})^x$

Solving:

We know 8= 2x2x2= 2^3

and $\sqrt[3]{x}=x^{\frac{1}{3}}$

Applying these rules:

$=((2^3)^{\frac{1}{3}})^x$

$=(2^{\frac{3}{3}})^x\\$

$=2^x$

So, solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Keywords: Radical Expression

Learn more about Radical Expression at:

#learnwithBrainly

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EASY PLZ HELP! Solve for x. (Show your work) 2x + 3 > 5

m_a_m_a [10]

Hi there!

Answer:

X>1

*The answer must have a positive sign and greater than symbol.*

Step-by-step explanation:

First, you subtract by 3 from both sides of an equation.

$2x+3-3>5-3$

Then, you subtract by the numbers from left to right.

$5-3=2$

$2x>2$

You can also divide by 2 from both sides of an equation.

$\frac{2x}{2}>\frac{2}{2}$

Finally, you divide by the numbers from left to right.

$2/2=1$

Final answer is x>1

I hope this helps you!

Have a nice day! :)

-Charlie

Thank you so much! :)

8 0

2 years ago

Read 2 more answers

The manager at the local auto shop has found that the probability that a car brought into the shop requires an oil change is 0.8

Ber [7]

Answer:

0.85

Step-by-step explanation:

Given two events A and B, the probability that either A or B occurs is given by:

$p(A\cup B) = p(A)+p(B)-p(A\cap B)$

where

$p(A)$ the probability that A occurs

$p(B)$ is the probability that B occurs

$p(A\cap B)$ is the probability that both A and B occur at the same time

In this problem, we know the following facts:

$p(o) = 0.83$ is the probability that the car requires an oil change

$p(b)=0.17$ is the probability that the car requires a brake repair

$p(o\cap b) = 0.15$ is the probability that the car requires both an oil change and brake repair

Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:

$p(o\cup b)=p(o)+p(b)-p(o\cap b)=0.83+0.17-0.15 = 0.85$

4 0

3 years ago

The perimeter of a triangle is 34cm. What are the lengths of the sides if the first side is twice the length of the second side

dybincka [34]

Answer:

8sm, 16sm, 10sm

Step-by-step explanation:

the first side of the triangle: x

the other side of the triangle: 2x

the third side of the triangle: x+2

the perimeter of the triangle: x+2x+x+2=34

4x=32

x=8

2*8=16

8+2=10

4 0

1 year ago

Right Answer to theese three questions please???

Scilla [17]

I hope this helps you

4 0

2 years ago

The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.

malfutka [58]

The number of pencils sold on the first day is 5 pencils.

The number of notebooks sold on the first day is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day 35 notebooks.

Step-by-step explanation:

Given data,

The total number of notebooks in the store = 45 notebooks.
The total number of Pencils in the store = 15 pencils.
The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

In the first day :

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day = x

And, the number of notebooks sold on the first day = 2x (Twice as pencils).

In the second day :

The number of sale of notebooks and pencils are given by,

For every 7 notebooks sold, 2 pencils were sold.

The number of pencils sold on the second day = 2y

The number of notebooks sold on the second day = 7y

The equation is framed for number of notebooks sold on each day :

The number of notebooks sold ⇒ 2x + 7y = 45 -------(1)

The equation is framed for number of pencils sold on each day :

The number of pencils sold: x + 2y = 15 ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

2x + 7y = 45

- (2x + 4y) = 30

3y = 15

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day = x ⇒ 5 pencils

The number of notebooks sold on the first day = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day = 2y ⇒ 10 pencils

The number of notebooks sold on the second day = 7y ⇒ 35 notebooks.

8 0

2 years ago