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Alisiya [41]
4 years ago
15

Find the Greatest Common Factor of 6ab, 3a

Mathematics
1 answer:
Sidana [21]4 years ago
8 0
The greatest common factor is 3a
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Step-by-step explanation:

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The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

3 0
3 years ago
Find the base of a parallelogram with the area of 60 in.² and height of 4 inches use the formula for the area of the parallelogr
Alexxx [7]
A = bh
60 in.² = b(4)
60/4 = b
b = 15 inches

Hope this helped!
7 0
3 years ago
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