Answer:
Boiling point of gold is 1630 or 3239.15 K
Explanation:
We know,
Here and are temperature in degree centigrate and temperature in degree farhenite respectively.
So,
= 1630
We know,
So, 2966 = (2966+273.15) K = 3239.15 K
The outcome of the equation shows that there is no light energy proving that light energy was absorbed to get CH20; +602
Answer: one sixteenth
Explanation: Since we know the half life of Cobalt-60 is 5.3 years, and 21.2 years have passed, we can determine how many half lifes have passed by doing division:
21.2 / 5.3 = 4
Since four half lifes have passed, we need to set up the following:
1 / 2^4 (always raise the two to the number of half lifes that have passed, in this case, four have passed, which is what we determined up above!)
When you simplify this you get 1 / 16, which is answer D.
Answer:
ZnC4H10
Explanation:
The empirical formula of a compound refers to the formula that gives the simplest whole number ratio of each atoms of the elements in the compound.
The empirical formula is calculated thus:
The given percentages in the question represent the mass in grams of each element in the compound.
Zinc= 53%, C= 38.9%, H= 8.1% which represents 53g, 38.9g and 8.1g of each element respectively.
Molar Mass of Zn= 65.4 g/mol
Molar Mass of C= 12 g/mol
Molar Mass of H= 1 g/mol
Step 1: Divide the mass of each element by the molar mass given to convert to moles:
Zn= 53/65.4 = 0.81moles
C= 38.9/12 = 3.24moles
H= 8.1/1 = 8.1moles
Step 2: Divide each mole value by the smallest number of moles calculated, which is 0.81moles:
Zn= 0.81/0.81 = 1
C= 3.24/0.81 = 4
H= 8.1/0.81= 10
This is the mole ratio represented in the subscript of each element in the empirical formula:
That is, Zn (1) C (4) H (10)
Empirical formula= ZnC4H10