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3 years ago

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How many grams of calcium phosphate can be produced when 78.5 grams of calcium hydroxide reacts with excess phosphoric acid? Unb

alanced equation: H3PO4 + Ca(OH)2 → H2O + Ca3(PO4)2 So I balanced the equation as 2H3PO4 + 3Ca(OH)2 = 6H2O + Ca3(PO4)2 but now I am stuck

1 answer:

sasho [114]3 years ago

3 0

Once you balance the enquation you "switch partners" of the element (negative charge to positive charge)

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Explanation:

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For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

So, $n_i=2$ and $n_f=\infty$ (As the hydrogen has to ionize)

Thus,

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J$

$E_{ionization}=5.45\times 10^{-19}\ J$

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