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Svetlanka [38]
3 years ago
6

In which of the following cases does the reaction go to farthest to completion ?

Chemistry
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

k=10^{3}

Explanation:

k stand for equilibrium constants in terms of reaction

The higher the value of an equilibrium constant the faster the equilibrium reaction comes to completion.

Consider the example below:

R_{1}\ + R_{2}⇄P_{1}\ + P_{2}

where

The\ equilibrium\ constant\ K = \frac{P_{1}P_{2}}{R_{1}R_{2}}

For a faster reaction the numerator i.e. the right hand side of the equation have to be higher than the left hand side (the denominator). therefore the higher the numerator, the higher the value of the equilibrium constant and the faster the reaction get to completion thus option c is correct.

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3 years ago
The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
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Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

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Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J

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15,595.5 J=C\times 2.125^oC

C=7,339.05 J/^oC

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Enthaply of combustion of glucose= 2,780 kJ/mol.

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Energy released by the 0.007771 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J

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Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

21,603.01 J=7,339.05 J/^oC\times \Delta T'

\Delta T'=2.943^oC

2.943 °C temperature change from the combustion of the glucose has been taken place.

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