Im unsure :( maybe try looking up a calorie calculator
Answer:
yes great job you do know that you can make high voltage capacitors to store static electricity just look up ElectroBooms high voltage capacitor he made it's very useful if you want to learn more.
The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):
![\Delta H = \Delta H_{r} - \Delta H_{p}](https://tex.z-dn.net/?f=%20%5CDelta%20H%20%3D%20%5CDelta%20H_%7Br%7D%20-%20%5CDelta%20H_%7Bp%7D%20)
Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
Read more here:
brainly.com/question/11753370?referrer=searchResults
I hope it helps you!
Answer: The equation is written below.
Explanation:
![2PO_4^{3-}(aq)+Al_2(SO_4)_3(aq)\rightarrow 2AlPO_4(s)+3SO_4^{2-}(aq)](https://tex.z-dn.net/?f=2PO_4%5E%7B3-%7D%28aq%29%2BAl_2%28SO_4%29_3%28aq%29%5Crightarrow%202AlPO_4%28s%29%2B3SO_4%5E%7B2-%7D%28aq%29)
According to Stoichiometry of the reaction:
2 moles of phosphate ions reacts with 1 mole of aluminum sulfate to produce 2 moles of aluminum phosphate precipitate and 3 moles of sulfate ions.
Aluminum phosphate is an odorless and white crystalline solid
The chemical equation is written above.