All categories

3 years ago

Parts of a transverse wave include:

Physics

2 answers:

iris [78.8K]3 years ago

8 0

Answer:

Parts of a transverse wave include:

Crest - the highest point on the wave

Trough - the lowest point on the wave

Wavelength - the distance from one crest to the next crest, or one trough to the next trough

Amplitude - the displacement of the wave from the midpoint to the highest point (crest) or the lowest point (trough)

Explanation:

Use the internet Brother

abruzzese [7]3 years ago

4 0

Answer:

Parts of a transverse wave include:

Crest - the highest point on the wave

Trough - the lowest point on the wave

the answer is: WAVELENGTH - the distance from one crest to the next crest, or one trough to the next trough

Amplitude - the displacement of the wave from the midpoint to the highest point (crest) or the lowest point (trough)

Explanation:

You might be interested in

How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to

finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is $x=\sqrt{\frac{2\times EPE}{k}}$

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

$EPE=\frac{1}{2}kx^2$

Rewriting the above expression in terms of 'x', we get:

$x=\sqrt{\frac{2\times EPE}{k}}$

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

$x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m$

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

6 0

3 years ago

The space shuttle travels at a speed of about 7.6times10^3 m/s. The blink of an astronaut's eye lasts about 110 ms. How many foo

sveta [45]

Answer:

It covers distance of 9.15 football fields in the said time.

Explanation:

We know that

$Distance=Speed\times Time$

Thus distance covered in blinking of eye =

$Distance=7.6\times 10^{3}m/s\times 110\times 10^{-3}s\\\\Distance=836 meters$

Thus no of football fields= $\frac{936}{91.4}=9.15Fields$

7 0

3 years ago

How did mount st. Helen get its name

steposvetlana [31]

The modern name, Mount St. Helen's, was given to the volcanic peak in 1792 by seafarer and explorer Captain George Vancouver of the British Royal Navy. He named it in honor of fellow countryman Alleyne Fitzherbert, who held the title 'Baron St. Helen's.

5 0

3 years ago

What are the applied forces on a box that is at rest on a floor

lutik1710 [3]

The only force applied is gravity

4 0

3 years ago

Billiard ball A (0.35 kg) is struck such that it moves at 10 m/s toward a second identical ball (Ball B) initially at rest. Afte

timurjin [86]

Answer:

Explanation:

We shall apply law of conservation of momentum during the collision of ball A and B .

Total momentum before collision of A and B = .35 x 10 = 3.5 kg m/s

Let the velocity of B after collision be v .

Total momentum after collision = .35 x 2 + .35v

According to law of conservation of momentum

.35 x 2 + .35v = 3.5

.35 v = 2.8

v = 8 m /s .

The direction of B will be same as direction of A .

3 0

3 years ago