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Nina [5.8K]
3 years ago
8

When large amplitude sound vibrates the ear significantly, a _______ results.

Physics
2 answers:
scoundrel [369]3 years ago
7 0
The answer is D. The loudness of a sound, or volume of a sound wave, can be dictated by the abundance of the sound wave. Both pitch and volume can influence how "boisterous" a sound is and how it influences human ears particularly.
kondaur [170]3 years ago
4 0
D loud sound

Hope this helped:)
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Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, how far did she move it?
olya-2409 [2.1K]

Answer:

2 m

Explanation:

Work = force × distance

500 J = 250 N × d

d = 2 m

She moved the couch 2 meters.

5 0
4 years ago
Convection currents occur when _________ energy transfers between two parts of a fluid
valentinak56 [21]

Answer:

heat

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3 years ago
Prove that the volume of a cube that moves with a velocity vin
liq [111]

Answer:

Proof is given below

Explanation:

The length contraction is given by Δx = Δx' *√(1 - v² / c²)

where Δx' is the proper length and is measured in the frame where the object is at rest

Since the y' and z' axes are perpendicular to the direction of motion there is no contraction

So if you let V0 = Δy' * Δz' *Δx'

and V = Δy * Δz * Δx = Δy'* Δz' * Δx

Then

V = V0 * √(1 - v² / c²)

6 0
4 years ago
How does wavelength and frequency affect the speed?
kvasek [131]
Rather, an alteration in wavelength affects the frequency in an inverse manner. A doubling of the wavelength results in a halving of the frequency; yet the wave speed is not changed.
3 0
3 years ago
Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is  Av with A the cross section area and v the velocity,

so,

A_1V_1=A_2V_2

A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}

the diameter decreases 86% so

d_2 = 0.86d_1

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}

Thus, speed in smaller section is 48.6 m/s

3 0
3 years ago
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