Compare and contrast sound waves and electromagnetic waves. Any bs answers will be reported. Please hurry!!!
1 answer:
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Answer:
a) 2.063*10^-4
b) 1.75*10^-4
Explanation:
Given that: d= 1.628 mm = 1.628 x 10-3 I= 12 mA = 12.0 x 10-8 A The Cross-sectional area of the wire is:
a) <em>The Potential difference across a 2.00 in length of a 14-gauge copper </em>
<em> wire: </em>
L= 2.00 m
From Table Copper Resistivity = 1.72 x 10-8 S1 • m The Resistance of the Copper wire is:
=0.0165Ω
The Potential difference across the copper wire is:
V=IR
=2.063*10^-4
b) The Potential difference if the wire were made of Silver: From Table: Silver Resistivity p= 1.47 x 10-8 S1 • m
The Resistance of the Silver wire is:
=0.014Ω
The Potential difference across the Silver wire is:
V=IR
=1.75*10^-4
Explanation:
It is given that,
Displacement of the delivery truck, (due east)
Then the truck moves, (due south)
Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :
d = 4.03 km
Let is the direction of the truck’s displacement from the warehouse from south of east.
So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.