Answer:
Step-by-step explanation:
Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.
G = card drawn is green
Y = card drawn is yellow
E = card drawn is even-numbered
List:
Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}
2) P(G) = 5/8
3) P(G/E) = P(GE)/P(E)
GE = {G2, G4}
Hence P(G/E) = 2/5
4) GE = {G2, G4}
P(GE) = 2/8 = 1/4
5) P(G or E) = P(G)+P(E)-P(GE)
= 5/8 + 3/8-2/8 = 3/5
6) No there is common element as G2 and G4
Cannot be mutually exclusive
The answer is four because there's one line that is placed on the origin which makes it no solution because there's not supposed to be a line on the origin and number 1 is a solution because there are neither lines plotted on the origin and has parallel lines
1. 2 3/4 = 11/4(2 * 4 + 3)
2. 1 1/4 = 5/4(1 * 4 + 1)
11/4 * 5/4 = 55/16 OR 3 7/16 if simplified.
9514 1404 393
Answer:
B = (-4, 5)
Step-by-step explanation:
Reflection over the origin changes the signs of the coordinates.
(x, y) ⇒ (-x, -y)
(4, -5) ⇒ (-4, 5)
Point B is (-4, 5).
