Answer:
The most reasonable estimate for the O–S–O bond angle in hyposulfite = 106°
Explanation:
Hyposulphite (so₂²⁻) is polyatomic ion .
According to VSEPR model
Total elrctron pairs ![=\frac{1}{2} [V+X -C+A]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%5BV%2BX%20-C%2BA%5D)
V = Valence shell electrons of central element
X = No. of monovalent surrounding atoms
C = Cationic charge
A = Anionic charge
Total electron pairs ![=\frac{1}{2}[6+0-0+2]= 4](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5B6%2B0-0%2B2%5D%3D%204)
That is two bond pairs and two lone pairs
What do you need help with
Answer:
they have increasing atomic number either u go left to right across a leriod or go down a group
PbH4 will be formed as a result of a polar covalent bond between the H and the Pb.
Since H is more electronegative than the Pb, it is, thus, expected that the H would be able to pull the electron charge towards itself. This will result in the H being negative.
Based on this:
PbH4 would be expected to <span>have polar covalent bonds with a partial negative charges on the H atoms. </span>
Answer:
The longest wavelength of radiation with enough energy to break a carbon–carbon bond is 343.75 nm.
Explanation:
E = hc/λ
E: energy = 348 000 J / 6.022 x 10²³ = 5.7788 x 10⁻¹⁹ J
h: Planck's constant = 6.62607004 × 10⁻³⁴ J.s
c: speed of light = 299 792 458 m / s
λ: wavelength
λ = hc/E
λ = (6.62607004 × 10⁻³⁴ J.s x 299 792 458 m / s) / 5.7788 x 10⁻¹⁹J
λ = 3.4375 x 10⁻⁷ m
λ = 343.75 nm
