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lawyer [7]
3 years ago
12

In a particular game of​ chance, a wheel consists of 42 slots numbered​ 00, 0,​ 1, 2,...,40. To play the​ game, a metal ball is

spun around the wheel and is allowed to fall into one of the numbered slots. Determine the sample space for one spin of this game.
Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

The sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

Step-by-step explanation:

Consider the provided information.

In probability theory, the set of all possible outcomes or outcomes of that experiment is the sample space of an experiment or random trial. Using set notation, a sample space is usually denoted and the possible ordered outcomes are identified as elements in the set.

Here the possible number of elements in the set are 00, 0, 1, 2,...,40

The sample space is anything the ball can land on.

Thus, the sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

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The smallest square number which can be divisible by 11 and 5​
Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

\sqrt{55x}  =  \sqrt{5 \times 11 \times x}

the smallest value of x to make 55x a perfect square is....

x = 11 \times 5 = 55

Therefore the number is.... .

55x = 55(55) = 3025

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3 years ago
What are the like terms in the expression?
Anarel [89]
Since none of the terms have the same variables the like terms would be (A) because they are both constants
5 0
2 years ago
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A high school debate team of 4 is to be chosen from a class of 35. how many possible ways can the team be formed?
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Imagine there are 4 sits for fill for the debate team 
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ivanzaharov [21]

The student is incorrect, the actual x-intercept is (5, 0).

<h3>Is the student correct or incorrect?</h3>

Here we have the equation:

x + 2y = 5

The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

So the point (0, 5) can't be an x-intercept.

For the given function:

x +2y = 5

The x-intercept is given by:

x + 2*0 = 5

x = 5

So it is (5 , 0).

If you want to learn more about x-intercepts:

brainly.com/question/3951754

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