Answer:
C.) for priority-based scheduling algorithms
Explanation:
for priority-based scheduling algorithms
Answer:
public static boolean isReverse(int [ ]a, int [ ]b ){
for (int i=0;i<a.length;i++)
{
if(!(a[i] == b[a.length-i-1]))
return false;
}
return true;
}
Explanation:
Using a for loop, we go through the elements of the first array. The if comapres and checks if any of the values are not the same as the appropriate value on the other array, if it is so, then it is not a reverse, and we return false. else we return true.
Answer:
Step 1: Identify the Problem
Step 2: Review the Literature. ...
Step 3: Clarify the Problem Step 4: Clearly Define Terms and Concepts.
Four computer languages i think
