Answer:
7.65x10^3 m/s
Explanation:
The computation of the satellite's orbital speed is shown below:
Given that
Earth mass, M_e = 5.97 × 10^24 kg
Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg
Orbital radius, r = 6.80 × 10^6m
Based on the above information
the satellite's orbital speed is
V_o = √GM_e ÷ √r
= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6
= 7.65x10^3 m/s
A because helium is in balloons and it’s lifting the balloon. Hope this helps!
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Answer:
A. It will continue traveling at the same speed.
Explanation:
I'm not 100% sure on this answer, but if I had this question I would be confident in this answer. It makes sense because unbalanced forces cause an object to start, stop, slow down, or speed up. Without these forces, the object should just keep traveling at the same speed.
I hope this helps! Let me know if it's right or not. ☺
