What particles bond together to

Physics

2 answers:

yanalaym [24]2 years ago

5 0

Answer:

atoms bond together and forms molecules

djyliett [7]2 years ago

4 0

Answer:

Atoms

Explanation:

this is because when atoms join or bond together forms a molecule

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Hey guys.. what’s 1,893,9379 x 0

MakcuM [25]

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3 years ago

What does this mean Atoms and elements are the basic back bone of the universe .

il63 [147K]

It means every thing is made out of Atoms and some things are element componds so elements are the "backbone" of the compounds.

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2 years ago

An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only

topjm [15]

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² = 1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities are inversely proportional to square root of their masses .

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2 years ago

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1

notka56 [123]

Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is $F_{net}= 3.22*10^{-5} \ J$