Option A is the correct answer.
If l and m both are doubled then the period becomes √2*T
what is a simple pendulum?
It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.
A pendulum is a weight suspended from a pivot so that it can swing freely.
Here,
A certain frictionless simple pendulum having a length l and mass m
mass of pendulum = m
length of the pendulum = l
The period of simple pendulum is:
![T = 2\pi \sqrt{\frac{l}{g} }](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%20%7D)
Where k is the constant.
Now the length and mass are doubled,
m' = 2m
l' = 2l
![T' = 2\pi \sqrt{\frac{2l}{g} }](https://tex.z-dn.net/?f=T%27%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7B2l%7D%7Bg%7D%20%7D)
![T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }](https://tex.z-dn.net/?f=T%27%20%3D%20%5Csqrt%7B2%7D%2A%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%20%7D)
![T' = \sqrt{2} * T](https://tex.z-dn.net/?f=T%27%20%3D%20%5Csqrt%7B2%7D%20%2A%20T)
Hence,
If l and m both are doubled then the period becomes √2*T
Learn more about Simple Harmonic Motion here:
<u>brainly.com/question/17315536</u>
#SPJ4
To develop this problem it is necessary to apply the concept of Frequency based on speed and wavelength.
According to the definition the frequency can be expressed as
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
Where,
v = Velocity
Wavelength
Our value are given by,
v = 345m/s
![\lambda = 63cm](https://tex.z-dn.net/?f=%5Clambda%20%3D%2063cm)
Replacing
![f = \frac{345}{0.63}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B345%7D%7B0.63%7D)
![f = 547.61Hz](https://tex.z-dn.net/?f=f%20%3D%20547.61Hz)
Therefore the frequency of the tuning fork is 547.61Hz
12.00 min = 0.2 hr
8.00 min = 0.15 hr
Total distance:
(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) + (20.0 km/hr) (0.2 hr)
= 8.25 km
Average speed:
(10.0 km/hr + 15.0 km/hr + 20.0 km/hr) / 3
= 15 km/hr
Change in position:
(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) - (20.0 km/hr) (0.2 hr)
= 0.25 km
Average velocity:
(10.0 km/hr + 15.0 km/hr - 20.0 km/hr) / 3
≈ 1.67 m/s
Gravity
The moon doesn't smash into the earth because the gravity from the earth keeps the moon in orbit around it.