Answer:
q = -2 m and q = -0.5 m
Explanation:
For this exercise we must use the equation of the optical constructor
1 / f = 1 / p + 1 / q
where f is the focal length, p and q are the distance to the object and the image, respectively
Let's start with the far vision point, in this case the power of the lens is
P = -0.5D
power is defined as the inverse of the focal length in meter
f = 1 / D
f = -1 / 0.5
f = - 2m
the object for the far vision point is at infinity p = infinity
1 / f = 1 / p + i / q
1 / q = 1 / f - 1 / p
1 / q = -1/2 - 1 / ∞
q = -2 m
The sign indicates that the image is on the same side as the object
Now let's lock the near view point
D = +2.00 D
f = 1 / D
f = 0.5m
the near mink point is p = 25 cm = 0.25 m
1 / f = 1 / p + 1 / q
1 / q = 1 / f - 1 / p
1 / q = 1 / 0.5 - 1 / 0.25
1 / q = -2
q = -0.5 m
the sign indicates that the image is on the same side as the object in front of the lens
<span>It also doubles
The gravitational force between two masses is expressed as:
F = G*m1*m2/r^2
where
F = Force between the two masses
m1 = Mass of object 1
m2 = Mass of object 2
r = distance between centers of object 1 and object 2
G = Gravitational constant
The exact values of G, m1, m2, and r don't matter since all except for m1 is held constant. And when m1 suddenly doubles, the force attracting the two object to each other also doubles.</span>
Mechanical advantage is a measure of the force amplification achieved by using a tool.
<span>A tidally locked body in synchronous rotation (the moon) takes just as long to rotate around its own axis as it </span>does<span> to revolve around its partner (the earth). In other words, the moon spins on its axis at the same rate it orbits the earth.</span>
Ac=centripetal accelration
Fc= centripetal force
V= tangential speed
