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2 years ago

Where is the acceleration zero?

Physics

1 answer:

ladessa [460]2 years ago

3 0

Answer:

When acceleration is zero (that is, a = dv/dt = 0), rate of change of velocity is zero. That is, acceleration is zero when the velocity of the object is constant. so probably D

Explanation:

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A man standing on top of a 30 m tall building throws a brick downwards with a velocity of 12 m/s. Determine the speed of the bri

loris [4]

Answer:

27.1m/s

Explanation:

Given parameters:

Height of the building = 30m

Initial velocity = 12m/s

Unknown:

Final velocity = ?

Solution:

We apply one of the kinematics equation to solve this problem:

v² = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

v² = 12² + (2 x 9.8 x 30)

v = 27.1m/s

3 0

3 years ago

What can be found by counting the number of troughs per second in a wave diagram

QveST [7]

Frequency can be found by counting the number of troughs per second in a wave diagram.

6 0

3 years ago

Two equally charged insulating balls each weigh 0.16 g and hang from a common point by identical threads 35 cm long. The balls r

Dafna11 [192]

Answer:

Q₁ = Q₂ = 8.84 x 10⁻⁹ C

Explanation:

given,

mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg

ball each other, r = 6.8 cm

Weight of the ball

F_w = m g

F_w = 1.6 x 10⁻⁴ x 9.8

F_w = 1.56 x 10⁻³ N

The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.

we have to find the horizontal component of the forces.

The length of the string,L is 35 cm so, it will be the hypotenuse.

θ be the angle made with imaginary vertical line and the string.

now,

$sin \theta = \dfrac{r\2}{L}$

$sin \theta = \dfrac{3.4}{35}$

θ = 5.57°

horizontal component of the force = ?

vertical component of force,F_v = 1.56 x 10⁻³ N

$tan\theta = \dfrac{F_H}{F_v}$

$tan(5.57^0) = \dfrac{F_H}{1.56\times 10^{-3}}$

F_h = 1.52 x 10⁻⁴ N

now, each ball will be repelled by

F = 1.52 x 10⁻⁴ N

now calculation of charges

$F = \dfrac{kQ_1Q_2}{r^2}$

Q₁ = Q₂ because both charge are same

$1.52\times 10^{-4} = \dfrac{9\times10^9Q^2}{0.068^2}$

Q² = 7.809 x 10⁻¹⁷

Q = 8.84 x 10⁻⁹ C

hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C

5 0

3 years ago

Calculate the weight of a 4.3 kg bunny WITH PROOF/WORK

ValentinkaMS [17]

In pounds? Cuz if so 2.2 x 4.3 = 9.46

3 0

2 years ago

Why should a spacecraft be airtight.

salantis [7]

Pressure outside of a spacecraft is different from pressure inside the spacecraft. If it is not airtight. It will cause an explosion due to fast pressure change!

7 0

3 years ago