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Vsevolod [243]
3 years ago
8

The part of a vompressional wave that has the lowest density is the

Physics
1 answer:
Yuri [45]3 years ago
8 0
Longitudinal waves have energy that vibrates parallel to the medium - a compression is the region of greatest density and the rarefaction the region of highest density .The rarefaction (much like the maximum amplitude in a transverse wave) has a region of lowest density, typically situated in the exact center of the region.
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Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?
kotykmax [81]

Answer:

250N

Explanation:

Given parameters:

Time  = 4s

Momentum  = 1000kgm/s

Unknown:

Force  = ?

Solution:

To solve this problem, we use Newton's second law of motion;

      Ft  = Momentum

F is the force

t is the time

So;

          F x 4 = 1000kgm/s

          F  = 250N

6 0
3 years ago
Please help I literally don’t understand
Veseljchak [2.6K]

Answer:

A= 2

B=3

C=4

D=5

E=7

F=8

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7 0
3 years ago
Question 7 (1 point)
Temka [501]

Answer:

Forms over water, warm humid air mass, it's a polar air mass

Explanation: I think that's right sorry if it's not..

GL! :)

4 0
3 years ago
During a very quick stop, a car decelerates at 7.6 m/s2. Assume the forward motion of the car corresponds to a positive directio
Mashcka [7]

Answer:

24.57 revolutions

Explanation:

(a) If they do not slip on the pavement, then the angular acceleration is

\alpha = a / r = 7.6 / 0.26 = 29.23 rad/s^2

(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where v = 0 m/s is the final angular velocity of the wheel when it stops, \omega_0 = 95rad/s is the initial angular velocity of the wheel, \alpha = -29.23 rad/s^2 is the deceleration of the wheel, and \Delta \theta is the angle swept in rad, which we care looking for:

0 - 95^2 = 2*29.23\Delta \theta

9025 = 58.46 \Delta \theta

\Delta \theta = 9025 / 58.46 = 154.375 rad

As each revolution equals to 2π, the total revolution it makes before stop is

154.375 / 2π = 24.57 revolutions

8 0
3 years ago
If sulfur 34 undergoes alpha decay, what will I become?
ikadub [295]
It will decay into Silicon-30. Because alpha particles are 2 protons and 2 neutrons with an atomic mass of 4, you minus sulfur's atomic number by 2 and get silicon. And the atomic mass is 34 - 4 which equals 30.
3 0
4 years ago
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