Answer:
The last option is correct
ΔT1 = 4 sec ΔT2 = 4 sec ΔT3 = 4 sec
S = V0 t + 1/2 a t^2
S1 = 1/2 a t^2 = 8 a where V0 is the speed at the start of the interval
During any interval (of 4 sec) the particle travels 1/2 a t^2 = 8 a due to its acceleration - and you need to include the speed at the start of the interval
S1 = 8a
S2 = 8 a + 8 a = 16 a
S3 = 16 a + 8 a = 24 a
Note: V2 = V1 + a t for any interval
V2 - V1 = V1 + a t - V1 = a t
and a = (V2 - V1) / t = a the speed increase is constant during the interval
The answer is homocysteine hehe hope this helps
The anwser is a even bigger wave is coming
Answer:
0.248 m
Explanation:
The period of a simple pendulum is given by

where
L is the length of the pendulum
g is the acceleration of gravity
The pendulum in the problem passes its lowest point twice every second: this means: this means that it makes one complete oscillation in one second, so its period is 1 second:
T = 1 s
And using

We can rearrange the equation above to find L, the length of the pendulum:
