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Lostsunrise [7]
3 years ago
6

(14pts) Please help me with this question on my homework

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

Step-by-step explanation:

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Find y when x=9 if y varies directly as the square of x, and y=100 when x=5.
sukhopar [10]
If y varies directly as the square of x, that means that y=k*x^2. Plugging y=100 and x=5 into it, we get 100=k*5^2=k*25. Dividing by both sides, we get k=100/25=4. Going back to the original equation, we now know that y=4*x^2. Plugging 9=x in, we get 4*9^2=4*81=324=y
7 0
3 years ago
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Need help asap pls and ty.
Anastasy [175]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
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Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
4 years ago
Can u help solve for x 3(x-4)-12=2(x-6)+8
Igoryamba

Answer:

{ \rm{3(x - 4) - 12 = 2(x - 6) + 8}} \\  \\   { \rm{3x - 12 - 12 = 2x - 12 + 8}} \\  \\ { \rm{3x - 24 = 2x - 4}} \\  \\ { \rm{3x - 2x = - 4 + 24}} \\  \\ { \rm{x = 20}}

4 0
3 years ago
Does anyone know this? I’m really stuck
S_A_V [24]

<em>p = 21</em>

Step-by-step explanation:

When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.

This is the equation we will be using.

2(p-13)=p-5

Now let's solve! Let's start by distributing the 2 by what's in the parentheses.

2p-26=p-5

Subtract p from both sides.

p-26=-5

Add 26 to both sides.

<u>p = 21</u>

7 0
3 years ago
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