Answer:
it didnt pop up the first time to answer
Step-by-step explanation:
go to de sm os and type in the equation and it will give you everything you need
Answer:
![\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D%20%7D)
Step-by-step explanation:
![A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-3%29%28-3%29%2B%284%29%28-2%29%26%28-3%29%284%29%2B%284%29%280%29%5C%5C%28-2%29%28-3%29%2B%280%29%28-2%29%26%28-2%29%284%29%2B%280%29%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D)
Answer:
The two numbers are 58 and 60
Step-by-step explanation:
let the two numbers be x and y
then:
y+3x=234
since the two numbers are consecutive even integers then y=x+2
and since y+3x=234
then (x+2)+3x=234
then 4x+2=234
then 4x=234–2
then x=232/4=58
then the other number (y) = x+2= 58+2=60
Answer: did you get the answer????
Step-by-step explanation:
