Consider using the Law of Cosines, because the lengths of three sides are given and the largest angle is the one to be approximated. This angle will be opposite the longest side, that is, opposite the 420-foot side.
420^2 = 250^2 + 300^2 - 2(250)(300)cos A.
Then: 176400 = 62500 + 810000 - 150000cos A.
Solving for cos A, we get:
150000cos A = 176400-62500-810000, or -696100
Then:
-696100
cos A = ------------------- = - 4.64. This is not possible, as the range of the cosine
150000 function is [-1,1].
You can just set y=0 and solve for x. when you do this you should get 1/2x^2=4
x^2=8
x=2.8 and -2.8 ( you have both a positive number and negative number since (-2.8)^2=(2.8)^2 =8
I hope this helps
Answer:
52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability that a randomly selected airfare between these two cities will be between $325 and $425?
This is the pvalue of Z when X = 425 subtracted by the pvalue of Z when X = 325. So
X = 425



has a pvalue of 0.7088
X = 325



has a pvalue of 0.1814
0.7088 - 0.1814 = 0.5274
52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425