3 years ago

Find the area of the smaller sector

1 answer:

3 0

Since the radius is 6 inches, the area is

$A=\pi r^2=36\pi$ squared inches.

Now, the full circle is a sector given by a 360° angle. So, the area of a 140° angle will be proportionate:

$140\div x = 360\div 36\pi$

Solving for $x$ , we have

$x=\dfrac{36\pi\cdot 140}{360}=14\pi$

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GenaCL600 [577]

Answer:

The common difference (or common ratio) = 0.75

Step-by-step explanation:

i) let the first term be $a_{1}$ = 80

ii) let the second term be $a_{2}$ = $a_{1}$ . r = 80 × r = 60 ∴ r = $\frac{60}{80}$ = 0.75

iii) let the third term be $a_{3}$ = $a_{2}$ . r = 60 × r = 45 ∴ r = $\frac{45}{60}$ = 0.75

iv) let the fourth term be $a_{4}$ = $a_{3}$ . r = 45 × r = 33.75 ∴ r = $\frac{33.75}{45}$ = 0.75

Therefore we can see that the series of numbers are part of a geometric progression and the first term is 80 and the common ratio = 0.75.

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GrogVix [38]

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Find the area of the smaller sector ​