Can find error , suppose to print what season it is and if fails : Traceback (most recent call last):
1 answer:
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Answer:
Step by step code along with explanation and output is given below
Explanation:
We can solve this problem using if elif else approach
def main():
# prompts the user to enter an integer from 1 to 10
num = int (input('Enter a number in the range of 1 to 10:\n'))
# using the if elif print out the roman numeral from 1 to 10
if num == 1:
print ('Roman Numeral for 1 is I')
elif num == 2:
print ('Roman Numeral for 2 is II')
elif num == 3:
print ('Roman Numeral for 3 is III')
elif num == 4:
print ('Roman Numeral for 4 is IV')
elif num == 5:
print ('Roman Numeral for 5 is V')
elif num == 6:
print ('Roman Numeral for 6 is VI')
elif num == 7:
print ('Roman Numeral for 7 is VII')
elif num == 8:
print ('Roman Numeral for 8 is VIII')
elif num == 9:
print ('Roman Numeral for 9 is IX')
elif num == 10:
print ('Roman Numeral for 10 is X')
# using the else print out error message whenever user enters any other number not listed above
else:
print ('Error! Wrong Input')
# call the main function
main()
Output:
Enter a number in the range of 1 to 10:
6
Roman Numeral for 6 is VI
Enter a number in the range of 1 to 10:
15
Error! Wrong Input
