Hi! Do you still need help! If so I would be more than glad to help!
A quality I would say of a physical substance is hardness
One mole of aluminum oxide or Al₂O₃ is 102 g/mol . It contains 54 g of Al metal. Thus, 25.5 tones of aluminum oxide contains 13.5 tones of Al. Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones.
<h3>What is aluminum?</h3>
Aluminum is 13 the element in periodic table. It is an electropositive element and exhibit metallic properties. Aluminum easily forms its oxides by reacting with atmospheric oxygen.
The molar mass of aluminum oxide Al₂O₃ is 102 g/mol. The atomic mass of Al is 27 g/mol. Thus 102 g of Al₂O₃ contains 54 g of Al. Therefore, the mass of Al in 25.5 tones or 25.5 ×10⁶ g of Al₂O₃ is calculated as follows:
mass of Al = (25.5 ×10⁶ g × 54 g) / 102 g
= 13.5 ×10⁶ g = 13.5 tones.
Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones
To find more on aluminum, refer here:
brainly.com/question/12768349
#SPJ1
The amount of Mg(OH)2 present after the reaction is complete is 0.136 moles of Mg(OH)2.
The equation of the reaction is;
2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)
Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles
Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles
Given that;
2 moles of HNO3 reacts with 1 mole of Mg(OH)2
0.00496 moles of HNO3 reacts with 0.00496 moles × 1 mole /2 moles = 0.00248 moles of Mg(OH)2
Hence, Mg(OH)2 is the reactant in excess.
The amount of Mg(OH)2 remaining = Amount present - Amount reacted
Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2
Learn more: brainly.com/question/9743981
