Answer:
Both technicians A and B are right
Explanation:
A mass flow sensor (MAF sensor) is defined as a sensor which is normally used to estimate the mass flow rate of air that flows into an internal combustion engine. The estimated parameter is used at the engine control unit to ensure that the actual mass of fuel is supplied to the engine. A MAF sensor can also measures the density and amount of air flowing into the engine. In addition, a hot wire MAF sensor uses the electronics in the sensor itself to heat a wire 70°C above the temperature of the air entering the engine. Therefore, both technicians A and B are right.
<u>Answer:</u> The initial concentration of
are 0.0192 M and 0.0192 M respectively.
<u>Explanation:</u>
We are given:
Equilibrium concentration of HI = 0.030 M
Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)
For the given chemical equation:

<u>Initial:</u> x x -
<u>At eqllm:</u> x-c x-c 2c
Calculating the value of 'c'

The expression of
for above reaction follows:
![K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D)
We are given:

![[H_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BH_2%5D%3D%28x-c%29%3D%28x-0.015%29)
![[I_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BI_2%5D%3D%28x-c%29%3D%28x-0.015%29)
Putting values in above equation, we get:

Neglecting the value of x = 0.0108 M, because the initial concentration cannot be less than the equilibrium concentration.
x = 0.0192 M
Hence, the initial concentration of
are 0.0192 M and 0.0192 M respectively.
A model represents a place thing or idea. A made is a model as it shows a place and represents the place it’s showing such as a globe
Answer:
The expected ratio of half-lives for a reaction will be 5:1.
Explanation:
Integrated rate law for zero order kinetics is given as:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
= initial concentration
[A]=concentration at time t
k = rate constant
if, ![[A]=\frac{1}{2}[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B1%7D%7B2%7D%5BA_o%5D)
, the equation (1) becomes:
![t_{\frac{1}{2}}=\frac{[A_o]}{2k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B%5BA_o%5D%7D%7B2k%7D)
Half life when concentration was 0.05 M=
Half life when concentration was 0.01 M=
Ratio of half-lives will be:
![\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}](https://tex.z-dn.net/?f=%5Cfrac%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%27%7D%3D%5Cfrac%7B%5Cfrac%7B%5B0.05%20M%5D%7D%7B2k%7D%7D%7B%5Cfrac%7B%5B0.01%20M%5D%7D%7B2k%7D%7D%3D%5Cfrac%7B5%7D%7B1%7D)
The expected ratio of half-lives for a reaction will be 5:1.
Answer:
gravity
Explanation: its a force that pulls you down but you are never making contact with it