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Westkost [7]
3 years ago
14

Convert 76.8 cm to m.

Chemistry
1 answer:
kari74 [83]3 years ago
4 0

Answer:

0.768 m

Explanation:

1 cm = 0.01 m

76.8 cm * 0.01 m/ 1 cm

0.768 m

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Technician A says that a MAF sensor actually measures the density and amount of air flowing into the engine. Technician B says a
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Answer:

Both technicians A and B are right

Explanation:

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Equal molar amounts of H2 and I2 are placed into an evacuated container and heated to 445°C, where the following equilibrium is
Rus_ich [418]

<u>Answer:</u> The initial concentration of H_2\text{ and }I_2 are 0.0192 M and 0.0192 M respectively.

<u>Explanation:</u>

We are given:

Equilibrium concentration of HI = 0.030 M

Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)

For the given chemical equation:

                  H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>            x     x        -

<u>At eqllm:</u>     x-c    x-c     2c

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2c=0.030\\\\c=\frac{0.030}{2}=0.015M

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_{eq}=50.2

[H_2]=(x-c)=(x-0.015)

[I_2]=(x-c)=(x-0.015)

Putting values in above equation, we get:

50.2=\frac{(0.030)^2}{(x-0.015)\times (x-0.015)}\\\\x=0.0108,0.0192

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x = 0.0192 M

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3 years ago
Which of the following values would you expect for the ratio of half-lives for a reaction with starting concentrations of 0.05M
harkovskaia [24]

Answer:

The expected ratio of half-lives for a reaction will be 5:1.

Explanation:

Integrated rate law  for zero order kinetics is given as:

k=\frac{1}{t}([A_o]-[A])

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if, [A]=\frac{1}{2}[A_o]

t=t_{\frac{1}{2}}, the equation (1) becomes:

t_{\frac{1}{2}}=\frac{[A_o]}{2k}

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Ratio of half-lives will be:

\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}

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aalyn [17]

Answer:

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