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NemiM [27]
3 years ago
11

The larger of two numbers is four times the smaller number, and their difference is 18. Find the two numbers.

Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

x = 12 , y = 10

Step-by-step explanation:

Let x , y are two numbers.

x > y

1 ) Three times the greater is 18 times their

difference

3x = 18( x - y )

x = 6( x - y )

x = 6x - 6y

6y = 5x

y = 5x/6 ——-( 1 )

2 ) 4 times the smaller is 4 less than twice

the sum of the two

4y + 4 = 2 ( x + y )

2y + 2 = x + y

y = x -2 ——( 2 )

From ( 1 ) and ( 2 ) ,

5x/6 = x -2

( 5x /6 ) - x = -2

( 5x - 6x ) /6 = -2

-x = -12

x = 12

Put x = 12 in equation ( 2 ) , we get

y = 12 - 2

y = 10

Therefore ,

x = 12 , y = 10

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3 years ago
8. 36.8 = [11.5 – (2.5 X 3)]2
Anestetic [448]

Answer:

[11.5-(2.5*3)]^2=16

Step-by-step explanation:

We want to evaluate [11.5-(2.5*3)]^2

Let us evaluate within the parenthesis first:

[11.5-(2.5*3)]^2=[11.5-(7.5)]^2

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We again subtract within the bracket to obtain:

[11.5-(2.5*3)]^2=[4]^2

This finally gives us:

[11.5-(2.5*3)]^2=16

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By elimination:

y = 3x - 1

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Subtract the first equation from the second again

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Subtract x from both sides of the first equation

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