To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
9*9=81
(if it is wrong i am sorry!)
The sum of the set of x - values given to us is calculated as; ∑X = -1
<h3>How to find the the sum of a set of data?</h3>
We are given;
X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6
1) ∑X = X1 + X2 + X3 + X4
∑X = 2 + (-8) + 4 + 1 = -1
2) ∑Y = Y1 + Y2 + Y3 + Y4
∑Y = 3 + (-8) + 10 + 6
∑Y = -11
3) ∑ X² = X₁² + X₂² + X₃² + X₄²
∑X² = (2)² + (-8)² + (4)² + (1)²
∑X² = 85
4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²
∑X² = (-3)² + (-8)² + (10)² + (6)²
∑X² = 209
Complete question is;
Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²
Read more about Sum of data at; brainly.com/question/15858152
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Answer:
x = 17
Step-by-step explanation:
This is a right triangle so we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
15^2 + x^2 = (sqrt(514))^2
225 + x^2 = 514
Subtract 225 from each side
225-225 + x^2 = 514-225
x^2 =289
Take the square root of each side
sqrt(x^2) = sqrt(289)
x = 17
