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3 years ago

Find the slope of the line that contains the following points: (17, -12) and (17, 8)

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

m = undef

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (17, -12)

Point (17, 8)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{-12-8}{17-17}$
[Fraction - Denominator] Subtract: $\displaystyle m=\frac{-12-8}{0}$

We cannot divide anything by 0.

∴ Our slope m is undefined and it would be a vertical line if graphed.

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Quinzel earns $1254 each month. His total deductions are 20% of his pay. How much is deducted from his pay each month ?

vova2212 [387]

20% = 0.20

1254 x 0.20 = 250.80

so he has $250.80 deducted every month

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4 years ago

Yolanda used a reconciliation worksheet provided by her bank. Line 5 should equal line 6 at the end of the reconciliation, but i

forsale [732]

Answer is 19.99 dollars

Explanation:

Let us draw the reconciliatin done by Yolanda linewise

Banking reconciliation Worksheet Amount of Mega

1) Closing balance $ 345 89

2) the sum of any outstanding deposits or credits. 0.00

3) Sum of 1 and 2 345.89

4. sum of any outstanding checks or debits. $ 37 51 5.

5) (3)-(4) $ 308 38

6) checkbook balance. $ 328 37

7) Difference (6)-(5) $ 19.99

SInce difference is exactly 19.99 dollars Yolanda should look for the amount 19.99 dollars to find a solution to the problem i.e. to see the reason for the difference between lines 5 and 6

4 0

3 years ago

Read 2 more answers

An experiment consists on rolling a fair number cube. There are 6 possible outcomes: 1, 2, 3, 4, 5, and 6. Find the probability

dimulka [17.4K]

Answer:

Step-by-step explanation:

The only possible outcomes on the die are 1,2,3,4,5,6.

Since 7 is not in the possible outcome list, It is impossible to obtain a 7 on this 6-sided die.

If the question had asked for the probability of other values, it would have been 1/6, because you can get each number at least once every 6 rolls. This, however varies in terms of experimental probability

Hope this helps

3 0

3 years ago

the probability that a twelve year old has a brother or sister is 25%. suppose you survey 300 twelve year olds. about how many d

Genrish500 [490]

Answer:

n(B U S) = 75

Step-by-step explanation:

Explanation:-

Probability:-

P(E) = $\frac{number of elements events in E}{total number of elementary events in the random experiment}$

$P(E) = \frac{m}{n}$

Let 'B' be the event of having twelve year old brother

Let 'S' be the event of having twelve year old sister

given data P(BUS) = 0.25

given total survey n(survey) = 300

we have to find the value is n(BUS) =?

we will use probability definition we get, P( BUS) = $\frac{n(BUS)}{n(survey)}$

substitute given values, we will get solution

$0.25 = \frac{n(BUS)}{300}$

after cross multiplication , we get

n(BUS) = 0.25 X 300

n(BUS) = 75

3 0

3 years ago

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : p = 0.6

H₁ : p = 0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago