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Gnesinka [82]
3 years ago
12

An experiment consists on rolling a fair number cube. There are 6 possible outcomes: 1, 2, 3, 4, 5, and 6. Find the probability

P(rolling a 7).
Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

0

Step-by-step explanation:

The only possible outcomes on the die are 1,2,3,4,5,6.

Since 7 is not in the possible outcome list, It is impossible to obtain a 7 on this 6-sided die.

If the question <em>had </em>asked for the probability of other values, it would have been 1/6, because you can get each number at least once every 6 rolls. This, however varies in terms of experimental probability

Hope this helps

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Answer:

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(-2x³)(-4x²)

8x⁵

(-3x²)³

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(x³y⁵)/(xy²)

x²y³

2x³(10x)³

2000x⁶

(x⁷y²)/(x⁴y²)

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x⁻⁴

1/x⁴

(-21x⁵y²)/(7x⁴y⁵)

-(3x)/y³

3x⁻³

3/x³

(32x³y²z⁵)/(-8xyz²)

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...

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...

2c⁷

x⁻²

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x⁻³

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a⁴

x⁻⁴

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...

4c⁵

x²y⁻³

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x³y⁻²

(x³)/(y²)

When dividing monomials with the same base, ______________ the exponents

subtract

x²y³z⁻⁴

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multiply

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x⁻²y⁻³

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one

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(x/y)⁻¹

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4r⁻³(2r²)

8÷r

(x²/y²)⁻¹

y²/x²

2x³y⁻³(2x⁻¹y³)

4x²

(x³/y³)⁻¹

y³/x³

2y²(3x)

6y²x

(x/y)⁻²

y²/x²

4a³b²(3a⁻⁴b⁻³)

12÷(ab)

(x²/y²)⁻³

y⁶/x⁶

4r⁰

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(2/3)⁻²

9/4

(4xy)⁻¹

1÷(4xy)

(4/5)⁻²

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(x²/x⁻⁵)

x⁷

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x²y⁰

x²

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x²y³

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x⁰(x⁴)(x⁻⁶)

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Is it a monomial? y

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(-4x²y)²(-½xy²)

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