Question

A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker is 205 Pa how many moles of air are in the cooker

Answer 1

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

• P = 205 Pa

• V = 5.68 L

• n = ?

• R = 8314.46 Pa·L·mol⁻¹·K⁻¹

• T = 390.4 K

We input the data given by the problem:

• 205  Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And solve for n:

• n = 3.59x10⁻⁴ mol