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KiRa [710]
3 years ago
8

A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker i

s 205 Pa how many moles of air are in the cooker
Chemistry
1 answer:
Cloud [144]3 years ago
6 0

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the<em> PV=nRT formula</em>, where:

  • P = 205 Pa
  • V = 5.68 L
  • n = ?
  • R = 8314.46 Pa·L·mol⁻¹·K⁻¹
  • T = 390.4 K

We<u> input the data given by the problem</u>:

  • 205  Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And <u>solve for n</u>:

  • n = 3.59x10⁻⁴ mol
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CO_2 sublimes readily at 25°C. Which properties are usually associated with a compound that undergoes this kind of change?
antoniya [11.8K]

Explanation:

Sublimation is defined as a process in which solid state of a substance directly changes into vapor or gaseous state without undergoing liquid phase.

For example, naphthalene balls show sublimation at room temperature.

As this process does not cause any change in chemical composition of a substance. Hence, it is known as a physical process.

Similarly, when CO_{2} sublimes readily at 25^{o}C. This shows change in physical state of carbon dioxide is taking place, i.e, from solid to gaseous phase.

Thus, we can conclude that when CO_{2} sublimes readily at 25^{o}C then it means physical properties are usually associated with a compound that undergoes this kind of change.

4 0
2 years ago
N2(g) + 3H2(g) =&gt; 2NH3(g) Write the reaction again as a balanced reaction
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Answer:Consider the reaction N2(g) + 3H2(g) =; 2NH3(g). If hydrogen gas is added to this system at equilibrium, will the reaction shift towards reactants

8 0
2 years ago
A 40.2 g sample of a metal heated to 99.3°C is placed into a calorimeter containing 120 g of water at 21.8°C. The final temper
aliina [53]

Answer:

B) Iron (c=0.45 J/g°C)

Explanation:

Given that:-

Heat gain by water = Heat lost by metal

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)

For water:

Mass = 120 g

Initial temperature = 21.8 °C

Final temperature = 24.5 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 40.2 g

Initial temperature = 99.3 °C

Final temperature = 24.5 °C

Specific heat of metal = ?

So,  

120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)

40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184

40.2C_{metal}\left(99.3-24.5\right)=1355.616

C_{metal}=0.45\ J/g^0C

<u>This value corresponds to iron. Thus answer is B.</u>

3 0
3 years ago
How many moles are in 100g of carbon dioxide?
Fantom [35]

Answer:

A

Explanation:

First, let's find the molar mass of CO₂. This is 12 + 2(16) = 44 g/mole.

Now we can write 100g * (1 mole / 44g) = 2.27 mol, or A. Hope this helps!

7 0
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Hi there can i plz have help :)
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Answer:

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Explanation:

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