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3 years ago

8

A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker i

s 205 Pa how many moles of air are in the cooker

1 answer:

Cloud [144]3 years ago

6 0

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the<em> PV=nRT formula</em>, where:

P = 205 Pa

V = 5.68 L

n = ?

R = 8314.46 Pa·L·mol⁻¹·K⁻¹

T = 390.4 K

We<u> input the data given by the problem</u>:

205 Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And <u>solve for n</u>:

n = 3.59x10⁻⁴ mol

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Answer:

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Explanation:

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