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KiRa [710]
3 years ago
8

A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker i

s 205 Pa how many moles of air are in the cooker
Chemistry
1 answer:
Cloud [144]3 years ago
6 0

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the<em> PV=nRT formula</em>, where:

  • P = 205 Pa
  • V = 5.68 L
  • n = ?
  • R = 8314.46 Pa·L·mol⁻¹·K⁻¹
  • T = 390.4 K

We<u> input the data given by the problem</u>:

  • 205  Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And <u>solve for n</u>:

  • n = 3.59x10⁻⁴ mol
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If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

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P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

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