Question

2. Randy has a 500 g of water at 20°C. If he wants the final temperature of the water to be 75°C (the change in temperature will be 55°C), how many Joules of heat will he need to add? (Cwater = 4.184 J/(g°C)​

Answer 1

Answer:

115060 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 500 g

Initial temperature (T1) = 20 °C

Final temperature (T2) = 75 °C

Change in temperature (ΔT) = 55 °C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) required =?

The heat required to change the temperature of the water can obtained as follow:

Q = MCΔT

Q = 500 × 4.184 × 55

Q = 115060 J

Therefore, the heat needed to change the temperature of the water is 115060 J.