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Orlov [11]
3 years ago
10

2. Randy has a 500 g of water at 20°C. If he wants the final temperature of the water to be 75°C (the change in temperature will

be 55°C), how many Joules of heat will he need to add? (Cwater = 4.184 J/(g°C)​
Chemistry
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

115060 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 500 g

Initial temperature (T1) = 20 °C

Final temperature (T2) = 75 °C

Change in temperature (ΔT) = 55 °C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) required =?

The heat required to change the temperature of the water can obtained as follow:

Q = MCΔT

Q = 500 × 4.184 × 55

Q = 115060 J

Therefore, the heat needed to change the temperature of the water is 115060 J.

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Example:

Mass = ?

Density = 25 g/mL

Volume = 5 mL

therefore:

d = m / V

25 = m / 5

m = 25 x 5

m = 125 g

hope this helps!

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3 years ago
The northern lights and huge power surges in technology are both effects of what
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3 years ago
give the chemical composition of the followings : Name Chemical Composition Coal gas Water gas Producer gas Natural gas
Assoli18 [71]

Answer:

Below.

Explanation:

Coal gas is a mixture of a variety of gases: inflammable gases including, hydrogen, methane, ethylene, carbon monoxide and volatile hydrocarbons and small amounts of non flammable gases like nitrogen and carbon dioxide.

Water gas consists mainly of carbon monoxide and hydrogen.

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8 0
3 years ago
Write the balanced chemical equation for the reaction between aqueous sodium carbonate and
ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

7 0
3 years ago
if i add water to 100 mL of a 0.75 M NaOH solution un til the final volume is 165mL what will the molarity of the diluted soluti
ehidna [41]
Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
c₂(NaOH) = n₂(NaOH) ÷ V₂(NaOH).
c₂(NaOH) = 0,075 mol ÷ 0,165 L.
c₂(NaOH) = 0,454 mol/L.
7 0
4 years ago
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