<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
<u>Explanation:</u>
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
The equation given by Henry's law is:
......(1)
where,
= solubility of carbon dioxide in water = 0.161 g/100 mL
= Henry's constant = ?
= partial pressure of carbon dioxide = 760 mmHg
Putting values in equation 1, we get:
![760mmHg=K_H\times 0.161g/100mL\\\\K_H=\frac{760mmHg}{0.161g/100mL}=4720.5g.mmHg/100mL](https://tex.z-dn.net/?f=760mmHg%3DK_H%5Ctimes%200.161g%2F100mL%5C%5C%5C%5CK_H%3D%5Cfrac%7B760mmHg%7D%7B0.161g%2F100mL%7D%3D4720.5g.mmHg%2F100mL)
Now, calculating the pressure of carbon dioxide using equation 1, we get:
= solubility of carbon dioxide in water = 0.886 g/100 mL
= Henry's constant = 4720.5 g.mmHg/100 mL
= partial pressure of carbon dioxide = ?
Putting values in equation 1, we get:
![p_{CO_2}=4720.5g.mmHg/100mL\times 0.886g/100mL=4182.4mmHg](https://tex.z-dn.net/?f=p_%7BCO_2%7D%3D4720.5g.mmHg%2F100mL%5Ctimes%200.886g%2F100mL%3D4182.4mmHg)
Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg