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2 years ago

What the answer plsss

Mathematics

2 answers:

Mumz [18]2 years ago

6 0

I’m pretty sure it is 158

Lera25 [3.4K]2 years ago

3 0

Answer:

3 - 312

Step-by-step explanation:

6*8=48

48/2=24

11*10=110

11*6=66

8*11=88

24*2=48

66+88+110+48=312

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An elephant walked 30 miles in 3 hours ,how fas was the elphant walking?

Kryger [21]

Answer:

10 miles per hour

Step-by-step explanation:

speed= distance/time

30/3

=10

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3 years ago

What is the max value of x and the min value of x???

LUCKY_DIMON [66]

Max value of x is infinite and min value of x is 0

7 0

2 years ago

Read 2 more answers

What is the association and are there any outliers?

kifflom [539]

Answer:

Hi there!

The correct answer is: There is a moderately strong, negative, nonlinear between two variables. There is one outlier around (3,40)

Step-by-step explanation:

The association in a scatter plot should always include a description of the form, direction, and strength of the association.

Form: Is the association linear or nonlinear?

Direction: Is the association positive or negative?

Strength: Does the association appear to be strong, moderately strong, or weak?

Outliers: Do there appear to be any data points that are unusually far away from the general pattern?

4 0

2 years ago

HEEEEELPPPPPPP ASAP (20 pts!!!, will give u teh brainliest if ur explanation is good UwU)

garri49 [273]

Answer:

x=60

Step-by-step explanation:

So basically the sum of interior angle of a triangle is 180.

Add all the values and make it equal to 180.

x+3/2x+1/2x=180

Then find x

3x=180

x=180/3

x=60 degrees

5 0

3 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago