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Phantasy [73]
3 years ago
7

Is liters length metric, volume, or weight

Mathematics
1 answer:
jekas [21]3 years ago
3 0

Answer/Step-by-step explanation:

Liters are used in the metric system to define amounts of volume.

1 quart = 0.946 metric liters

1 gallon = 3.785 metric liters

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Y=5x+2 and 3x=-y+10 what is the soluion of equation
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Read 2 more answers
Write 2^8 * 8^2 * 4^-4 in the form 2^n
Eva8 [605]

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

<h3>What are exponential forms?</h3>

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

<u>For example:</u>

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

  • a is the base, and
  • 4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power. 

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }

\mathbf{= 2^8\times (2^6) \times (2^{-8}) }

\mathbf{= 2^{8+6+(-8)}}

\mathbf{= 2^{6}}

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

Learn more about exponential forms here:

brainly.com/question/8844911

#SPJ1

4 0
2 years ago
How to right f(x)=3x(x-8)+5 in standard form
Brums [2.3K]
Standard form of the parabola

8 0
3 years ago
2x-y=-1 , 3x-y=2 solve by substition
Mazyrski [523]

Answer:

x = 3, y = 7

or (3,7)

Step-by-step explanation:

We are given the system of equations below:

\large{ \begin{cases} 2x - y =  - 1 \\ 3x - y = 2 \end{cases}}

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

\large{ \begin{cases} y=  2x + 1\\ 3x - y = 2 \end{cases}}

Then we substitute y = 2x+1 in the second equation.

\large{3x - (2x + 1) = 2}

Use the distribution property.

\large{3x - 2x - 1 = 2}

Isolate x-term to solve the equation.

\large{x = 2 + 1} \\  \large{x = 3}

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

\large{2x - y =  - 1}  \\  \large{2(3) - y =  - 1} \\  \large{6 - y =  - 1}

Isolate and solve for y-term.

\large{6 + 1 = y} \\  \large{7 = y} \\  \large{y = 7}

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

7 0
3 years ago
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