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2 years ago

ILL MARK AS BRAINLIEST AND ILL GIVE 30 POINTS

Chemistry

1 answer:

Dovator [93]2 years ago

3 0

Answer:

polyatomic ions are ions they are composed of two range

1 binary ionic compounds nomenclature of ionic and contrbuture 2.brainly components between two nominees

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30. a. How do the properties of metals differ from those

Ahat [919]

Explanation:

Metals are elements that ionized by loss of electrons.

Ionic and molecular compounds are usually non-metals.

Properties of metals:

Metals have free mobile electrons and the metallic bonding ensures that.
They are usually electropositive and freely looses their electrons.
None of the metal is soluble without a chemical change occurring.
They are ductile and malleable.
Metals are good conductor or heat and electricity in their free uncombined state.
They are lustrous.

B. The specific property of metals accountable for their unusual electrical conductivity is due to the presence of free mobile electrons in their lattices.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

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3 years ago

What do cubic measurements, live cm3, mesure?"<br> O length<br> volume

anygoal [31]

The answer is volume.

6 0

2 years ago

Earth Science 10/ Chemistry 11

timama [110]

Measuring the ratio of C-14 to C-12 in the remains of dead organisms to determine how much time has passed since the organism died

the answer is D

6 0

3 years ago

PLSSS HELP FAST

Aliun [14]

Note the formula

$\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}$

For X:-

No of protons:-

$\\ \sf\longmapsto 19-10=9protons$

It is Fluorine.

For Y:-

No of protons:-

$\\ \sf\longmapsto 16-8=8protons$

It is Oxygen.

Option D is correct

7 0

2 years ago

The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is

WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

$sp^{3}$ , four electron domains, as in ethane $\text{C}_2\text{H}_6$
$sp^{2}$ , three electron domains, as in ethene $\text{C}_2\text{H}_4$
$sp$ , two electron domains, as in ethyne $\text{C}_2\text{H}_2$

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

Carbon atoms with a $sp^{3}$ hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately $109.5\textdegree{}$
Carbon atoms with a $sp^{2}$ hybridization would demonstrate a triangular planar configuration with a bond angle of $120\textdegree{}$
Carbon atoms with a $sp$ hybridization would demonstrate a linear configuration with a bond angle of $180\textdegree{}$

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

$sp^{3}$ in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
$sp^{2}$ in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.

3 0

3 years ago