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1 year ago

A when sulfuric acid is added to sirie, hydrager

1 answer:

8 0

Sulfuric acid is prepared industrially by means of the response of water with sulfur trioxide which in turn is made by way of a chemical combination of sulfur dioxide and oxygen both by way of the touch system or the chamber system.

H2SO4 (l) H2O (g) + SO3 (g).

The reaction is highly exothermic as an enormous amount of heat is liberated.

The usual approach is to dilute the sulfur trioxide in sulphuric acid. This produces oleum. SO3 (g) + H2SO4 → H2S2O7 (1) Oleum can be in addition diluted in water to acquire concentrated sulphuric acid.

An acid catalyst is added to protonate the carbonyl carbon. How does this catalyze the response, robust acid catalysts catalyze the hydrolysis and transesterification of esters which enables the mechanism with a view to boom the electrophilicity of the carbonyl carbon to assist protonate the carbonyl oxygen.

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HELP!!! IF YOU DONT KNOW THE ANSWER THEN PLEASE DONT ANSWER!!

Simora [160]

Answer:

1. melting

2. freezing

5. condensation

6. evaporation

4 0

3 years ago

In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z

storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0

3 years ago

How many moles are in 1.505x10^24 molecules of surcrose

algol [13]

Answer:

2.499 moles of sucrose

Explanation:

Divide by Avogadro's number

5 0

3 years ago

Calculate the percent by mass of potassium nitrate in a solution made from 45.0 g kno3 and 295 ml of water. The density of water

Tanzania [10]

Answer: the percent by mass of potassium nitrate is 13.3%

Explanation:

1) Data:

Mass of solute, m₁ = 45.0 g

Volume of solvent, V₂ = 295 ml

density of water, d₂ = 0.997 g/ml

2) Formulae:

Percent by mass, % = (mass of solute / mass of solution) × 100

Density, d = mass / volume

3) Solution:

d = mass / volume ⇒ m₂ = d₂ × V₂ = 0.997 g/ml × 295 ml = 294. g

mass of solution = m₁ + m₂ = 45.0g + 294. g = 339. g

% = (45.0 g / 339. g) × 100 = 13.3 %

The answer has to be reported with 3 significant figures.

6 0

3 years ago

How does soil form from bare rock

Masteriza [31]

Weathering and erosion produce smaller rock particles which, when mixed with dust result in different types of soil.

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3 0

3 years ago

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