First, let us calculate the moles of solute or sodium
bicarbonate is in the 1 ml solution.
<span>moles = 1 mL * (1 g
/ 9 mL) = 0.11 moles</span>
The molar mass of sodium bicarbonate is 84 g/mol,
therefore the mass is:
mass = 0.11 moles * 84 g/mol
<span>mass = 9.33 g</span>
The rate constant of the second order reaction is 0.137 M-1s-1.
<h3>What is the rate constant?</h3>
For the second order reaction we can write;
1/[A] = kt + 1/[A]o
[A]o = initial concentration
[A] = final concentration
k = rate constant
t = time
Now;
1/0.319 = 13.5k + 1/ 0.740
1/0.319 - 1/0.740 = 13.5k
3.13 - 1.35 = 13k
k = 3.13 - 1.35/13
k = 0.137 M-1s-1
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Answer:
Molality = 0.43 m
Explanation:
Given data:
Mass of barium sulfide = 25.4 g
Mass of water = 349 g (349 g/1000 = 0.349 Kg)
Molality of water = ?
Solution:
Number of moles of barium sulfide:
Number of moles = mass/molar mass
Number of moles = 25.4 g/169.39 g/mol
Number of moles = 0.15 mol
Molality:
Molality = number of moles o f solute/ Kg of solvent
Molality = 0.15 mol / 0.349 Kg
Molality = 0.43 m
The equation that is represented by the model is = x²-2x-3=(x − 3)(x + 1).
<h3>What are polynomials?</h3>
Polynomials are defined as the mathematical expression that is made up of variables.and coefficients.
The model is +X-x-x- ,
Which is X -2x ( negative minus negative is plus)
Therefore, the equation that is represented by the model is = x²-2x-3=(x − 3)(x + 1)
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Answer: mass and relative abundance of each isotope of that element
Explanation:-
For example:
If an element X has two isotopes with following masses ad abundance:
Mass of isotope 1 = 267.8 amu
% abundance of isotope 1 = 87.8% = 0.878
Mass of isotope 2 = 269.9 amu
% abundance of isotope 2 = 12.2% = 0.122
Formula used for average atomic mass of an element :

![\text{ Average atomic mass of an element X}=\sum[(267.8\times 0.878)+(269.9\times 0.122)]](https://tex.z-dn.net/?f=%5Ctext%7B%20Average%20atomic%20mass%20of%20an%20element%20X%7D%3D%5Csum%5B%28267.8%5Ctimes%200.878%29%2B%28269.9%5Ctimes%200.122%29%5D)
